SOLUTION: how do you graph y= x^2/2 -5?

 

Hi

Using the vertex form of a parabola,  where(h,k) is the vertex

y= .5x^2 -5  

1) Parabola 

2)Parabola with vertex Pt(0,-5)

3)  y-axis the line of symmetry

4) Parabola Opens Upward a = .5 >0

5) x-intercepts(when y = 0) are x =  ±