SOLUTION: y(3y+4)=0

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Question 435454: y(3y+4)=0

Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ay%5E2%2Bby%2Bc=0 (in our case 3y%5E2%2B4y%2B0+=+0) has the following solutons:

y%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%284%29%5E2-4%2A3%2A0=16.

Discriminant d=16 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-4%2B-sqrt%28+16+%29%29%2F2%5Ca.

y%5B1%5D+=+%28-%284%29%2Bsqrt%28+16+%29%29%2F2%5C3+=+0
y%5B2%5D+=+%28-%284%29-sqrt%28+16+%29%29%2F2%5C3+=+-1.33333333333333

Quadratic expression 3y%5E2%2B4y%2B0 can be factored:
3y%5E2%2B4y%2B0+=+3%28y-0%29%2A%28y--1.33333333333333%29
Again, the answer is: 0, -1.33333333333333. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B4%2Ax%2B0+%29