SOLUTION: Find three consecutive integers such that the product of the two largest is 20 more than the square of the smallest integer.

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Question 435380: Find three consecutive integers such that the product of the two largest is 20 more than the square of the smallest integer.
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
Let the three integers equal x, x+1, x+2.
(x+1)(x+2)-20=x2
x2+3x+2-20=x2
3x=18
x=6
x+1=7
x+2=8.