SOLUTION: what is the unknown of log1/2 16 + log1/3 9 = b
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Question 434978
:
what is the unknown of log1/2 16 + log1/3 9 = b
Answer by
stanbon(75887)
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what is the unknown of log1/2 16 + log1/3 9 = b
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log(1/2)(16) = -4
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log(1/3)9 = -2
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b = -4-2= -6
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Cheers,
Stan H.