SOLUTION: find the two consecutive integers such that the square of the smaller is 10 more than the larger

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Question 434925: find the two consecutive integers such that the square of the smaller is 10 more than the larger
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
call the consecutive integers n and n%2B1
given:
+n%5E2+=+n+%2B+1+%2B+10+
+n%5E2+=+n+%2B+11+
+n%5E2+-+n+=+11+
+n%5E2+-+n+%2B+%281%2F2%29%5E2+=+11+%2B+%281%2F2%29%5E2+
++n%5E2+-+n+%2B+1%2F4+=+44%2F4+%2B+1%2F4+
+%28+n+-+1%2F2%29%5E2+=+45%2F4+
+n+-+1%2F2+=+3%2Asqrt%285%29%2F2+
+n+=+%281+%2B+3%2Asqrt%285%29%29%2F2+
I can't make any sense of the problem.
Was it copied right?