SOLUTION: Find two consecutive integers whose product is 72. x= 1st integer x+1 + 2nd integer x(x+1) = 72 x^ + 1x + 72 x^ + 1x -72 = 0 (x+9)(x-8) so x=-9 and x=8 but these are

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find two consecutive integers whose product is 72. x= 1st integer x+1 + 2nd integer x(x+1) = 72 x^ + 1x + 72 x^ + 1x -72 = 0 (x+9)(x-8) so x=-9 and x=8 but these are       Log On


   

Question 434845: Find two consecutive integers whose product is 72.
x= 1st integer
x+1 + 2nd integer
x(x+1) = 72
x^ + 1x + 72
x^ + 1x -72 = 0
(x+9)(x-8)
so x=-9 and x=8
but these are not consecutive integers. I have to solve this using the GSSC model. did I do this right?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find two consecutive integers whose product is 72.
x= 1st integer
x+1 + 2nd integer
x(x+1) = 72
x^ + 1x + 72
x^ + 1x -72 = 0
(x+9)(x-8)
so x=-9 and x=8
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You have two separate solutions:
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If x = -9
then x+1 = -8
==================
If x = 8
then x+1 = 9
===================
Cheers,
Stan H.