SOLUTION: please help with this last one. Solve the quadratic equation by factoring 2x^2 = 19x + 33 thanks

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Question 43454This question is from textbook college algebra
: please help with this last one.
Solve the quadratic equation by factoring
2x^2 = 19x + 33
thanks
This question is from textbook college algebra

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve by factoring:
2x%5E2+=+19x+%2B+33 Rewrite in standard form.
2x%5E2+-+19x+-+33+=+0
The factors will be in the form: (2x+a)(x+b)
Look at the first term 2x%5E2 and determine that the obvious factors are:
%282x%29%28x%29+=+2x%5E2
Now look at the last (constant) term and determine the factors (a and b) of -33.
The choices are:
(a)(b)
(-1)(33) = -33
(1)(-33) = -33
(3)(-11) = -33
(-3)(11) = -33
Choose the pair from the above list such that: 2b+a = -19 which is the coefficient of the middle term of the rewritten quadratic equation.
The obvious choice is: a = 3 and b = -11 since 2(-11) + 3 = -22 + 3 = -19
Now you can write the factors of your quadratic equation:
2x%5E2-19x-33+=+%282x%2B3%29%28x-11%29 Now you can solve the quadratic equation.
%282x%2B3%29%28x-11%29+=+0 Apply the zero products principle.
2x%2B3+=+0 and/or x-11+=+0
If 2x%2B3+=+0 then 2x+=+-3 and x+=+-3%2F2
If x-11+=+0 then x+=+11
The roots are:
x+=+-3%2F2
x+=+11