You can put this solution on YOUR website! (tan x - cot x) / (tan^2 x - cot^2 x)= sin x cos x
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start with left side
(tan x - cot x) / (tan^2 x - cot^2 x)
difference of squares
(tan x - cot x) / (tan x - cot x)(tan x + cot x)
1/(tan x + cot x)
1/((sinx/cosx)+(cosx/sinx))
1/((sin^2x+cos^2x)/sinxcosx))
1/(1/sinxcosx)=sinxcosx
verified:
Left side=Right side