SOLUTION: When a person falls through the ice on a lake, the cold water removes body temperature 25 times faster that air at the same temperature. To survive, a person has between 30 to 90 s

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: When a person falls through the ice on a lake, the cold water removes body temperature 25 times faster that air at the same temperature. To survive, a person has between 30 to 90 s      Log On


   



Question 434084: When a person falls through the ice on a lake, the cold water removes body temperature 25 times faster that air at the same temperature. To survive, a person has between 30 to 90 seconds to get out of the water. How long could a person remain in air at the same temperature?
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
30 to 90 x 25=750 to 2250 seconds..