SOLUTION: 7(3x-2)^2-28=0 solve by extracting the roots

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Question 433905: 7(3x-2)^2-28=0
solve by extracting the roots
Answer by Alan3354(69443) About Me  (Show Source):
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7(3x-2)^2-28=0
(3x-2)^2-4=0
(3x-2)^2 = 4
3x-2 = 2
3x = 4
x = 4/3
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3x-2 = -2
3x = 0
x = 0