SOLUTION: I am pretty sure I have this under control but I would like to verify my answers.
(m^-3n^4)^-4
I got m^12/n^16 If this is not correct, please show me how.
(4x^4)3(2xy^3)2
I
Algebra ->
Exponents-negative-and-fractional
-> SOLUTION: I am pretty sure I have this under control but I would like to verify my answers.
(m^-3n^4)^-4
I got m^12/n^16 If this is not correct, please show me how.
(4x^4)3(2xy^3)2
I
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Question 433674: I am pretty sure I have this under control but I would like to verify my answers.
(m^-3n^4)^-4
I got m^12/n^16 If this is not correct, please show me how.
(4x^4)3(2xy^3)2
I got 256x^16y^3 yes?
one more
This is to be done in scientific notation.
10^-9x(2x10^2)^2 x is being used to mean "times"
I got 4x10^-5 somewhat more sketchy on this one!!
Thanks so much Answer by rwm(914) (Show Source):
You can put this solution on YOUR website! m^12/n^16 is fine
Limit yourself to one question per submission for archival purposes.
and one question of the same type per day.
Use * (shift 8) for times not x