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Question 433600: 1. One number is five times the other number. If the two numbers total 26, find the numbers.
2. A collection of nickels and dimes has a total value of $8.50. How many coins are there if there are three times as many nickels as dimes?
3. Find 2 consecutive numbers with a sum of 285.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 1. One number is five times the other number. If the two numbers total 26, find the numbers.
x = 5y
x+y = 26
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Substitute for "x" and solve for "y":
5y+y = 26
6y = 26
y = 13/3 = 4 1/3
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Solve for "x":
x = 5y
x = 5(13/3) = 65/3 = 21 2/3
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2. A collection of nickels and dimes has a total value of $8.50. How many coins are there if there are three times as many nickels as dimes?
Equations:
Quantity Eq: n = 3d
Value: 5n + 10d = 850 cents
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substitute for "n" and solve for "d":
5(3d) + 10d = 850
25d = 850
d = 34 (# of dimes)
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Solve for "n":
n = 3d
n = 3*34 = 102 (# of nickels)
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3. Find 2 consecutive numbers with a sum of 285.
1st: x
2nd: x+1
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Equation:
x + x+1 = 285
2x = 284
x = 142
x+1 = 143
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Cheers,
Stan H.
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