SOLUTION: A store sells cashews for $5.00 per pound and peanuts for $2.00 per pound. The manager decides to mix 10 pounds of peanuts with some cashews and sell the mixture for $3.00 per poun

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Question 433505: A store sells cashews for $5.00 per pound and peanuts for $2.00 per pound. The manager decides to mix 10 pounds of peanuts with some cashews and sell the mixture for $3.00 per pound. How many pounds of cashews should be mixed with the peanuts so that the mixture will produce the same revenue as would selling the nuts seperately?
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
Let cashews equal x, peanuts y. Then:
x + y=10
5x+2y=10*3=30
--------------
5x+2y=30
2x+2y=20
----------
3x=10
x=10/3
y=20/3
So, 10/3lbs. of cashews, 20/3lbs. of peanuts.
Solved by pluggable solver: Linear System solver (using determinant)
Solve:
+system%28+%0D%0A++++1%5Cx+%2B+1%5Cy+=+10%2C%0D%0A++++5%5Cx+%2B+2%5Cy+=+30+%29%0D%0A++

Any system of equations:


has solution

or



(x=3.33333333333333, y=6.66666666666667}