SOLUTION: Can you please show me steps to solve the following: (14x^3-5x^2-7x+7)/(2x-1)
I'm stuck. I have so far 7x^2-6x with -1x+7 remainder, I don't know what to do with the -1x+7.
T
Algebra ->
Divisibility and Prime Numbers
-> SOLUTION: Can you please show me steps to solve the following: (14x^3-5x^2-7x+7)/(2x-1)
I'm stuck. I have so far 7x^2-6x with -1x+7 remainder, I don't know what to do with the -1x+7.
T
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Question 433430: Can you please show me steps to solve the following: (14x^3-5x^2-7x+7)/(2x-1)
I'm stuck. I have so far 7x^2-6x with -1x+7 remainder, I don't know what to do with the -1x+7.
Thank you. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! please show me steps to solve the following: (14x^3-5x^2-7x+7)/(2x-1)
----------------
.........7x^2+x+4
(2x-1) )14x^3-5x^2-7x+7
........14x^3-7x^2
--------------------------
.............2x^2-7x+7
.............2x^2-x
--------------------------
.................8x+7
.................8x-4
---------------------------
....................11
===
Quotient: 7x^2+x+4
Remainder: 11
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Note: This long-division problem may appear
all mixed up when you see it, even though
it looked find when I typed it. That is why
we avoid trying to perform long-division on
this site.
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Cheers,
Stan H.
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