SOLUTION: I have to subtract as indicated and simplify the results if possible. Can someone show me how to do this?
6y/y^2-4 - 3/y+2
The 6y is over the y^2-4 and the 3 is over the y+2
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-> SOLUTION: I have to subtract as indicated and simplify the results if possible. Can someone show me how to do this?
6y/y^2-4 - 3/y+2
The 6y is over the y^2-4 and the 3 is over the y+2
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Question 43338: I have to subtract as indicated and simplify the results if possible. Can someone show me how to do this?
6y/y^2-4 - 3/y+2
The 6y is over the y^2-4 and the 3 is over the y+2 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! (6y)/(y^2-4) - (3)/(y+2)
The least common denominator (LCD) is (y+2)(y-2)=y^2-4
Convert each fraction so each has the LCD as its denominator, as follows:
(6y)/(y^2-4) - [3(y-2)]/(y^2-4)
Subtract as indicated:
[6y-3(y-2)]/(y^2-4)
[3y+6]/(y^2-4)
Factor to get:
[3(y+2)]/[(y+2)(y-2)]
=3/(y-2)
Cheers,
stan H.
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