SOLUTION: An aircraft flew 6 hours with the wind. The return trip took 7 hours against the wind.If the speed of the plane in still air is 492 miles per hour more than the speed of the wind,

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Question 433323: An aircraft flew 6 hours with the wind. The return trip took 7 hours against the wind.If the speed of the plane in still air is 492 miles per hour more than the speed of the wind, find the wind speed and the speed of the plane in still air.
The wind speed was__mph.
The speed of the plane in still air is___ mph.
Help please.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
An aircraft flew 6 hours with the wind. The return trip took 7 hours against the wind.If the speed of the plane in still air is 492 miles per hour more than the speed of the wind, find the wind speed and the speed of the plane in still air.
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With-wind DATA:
time = 6 hrs. ; rate = 492+w ; distance = 6(492+w) miles
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Against-wind DATA:
time = 7 hrs. ; rate = 492-w ; distance = 7(492-w) miles
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Equation:
miles = miles
6(492+w) = 7(492-w)
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6*492+6w = 7*492-7w
13w = 492
w = 37.846 mph (wind rate)
plane speed in still air: 492 mph

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Cheers,
Stan H.