SOLUTION: Give the equation of the line that is perpendicular to the line y = -3x + 7 and passes through
point (0, -6).
A) y =13x + 6
B) y = -13x - 6
C) y = -3x - 6
D) y =13x - 6
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-> SOLUTION: Give the equation of the line that is perpendicular to the line y = -3x + 7 and passes through
point (0, -6).
A) y =13x + 6
B) y = -13x - 6
C) y = -3x - 6
D) y =13x - 6
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Question 433317: Give the equation of the line that is perpendicular to the line y = -3x + 7 and passes through
point (0, -6).
A) y =13x + 6
B) y = -13x - 6
C) y = -3x - 6
D) y =13x - 6 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Give the equation of the line that is perpendicular to the line y = -3x + 7 and passes through
point (0, -6).
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The listed equation has slope = -3,
so the perpendicular line must have
slope 1/3
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Form: y = mx+b
-6 = (1/3)*0+b
b = -6
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Equation:
y = (1/3)x-6
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Cheers,
Stan H.
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Sorry the slections are as follows:
A) y=1/3x+6
B)y=-1/3x-6
C)y=-3x-6
D)y=1/3x-6
(