Question 433292: how do you graph the equation 49-7y=0
I honestly have not tried anything yet. I am unclear of how to do this. I do online classes and am having a difficult time getting my teacher to respond to my email.
Any help would be greatly appreciated :)
Found 2 solutions by stanbon, algebrahouse.com:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! graph the equation 49-7y=0
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7y = 49
y = 7
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Let x = 0, then y = 7 giving you point (0,7)
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Let x = 2, then y = 7 giving you point (2,7)
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Plot the two points and draw a line thru them
to get:
Cheers,
Stan H.
Answer by algebrahouse.com(1659)  (Show Source):
You can put this solution on YOUR website! "how do you graph the equation 49-7y=0"
Slope-intercept form is y = mx + b
m is the slope of the line
b is the y-intercept of the line {where it crosses the y-axis
49 - 7y = 0
7y = 49 {added 7y to both sides}
y = 7 {divided both sides by 7 to get into slope-intercept form}
this could be written as y = 0x + 7
slope = 0
y-intercept = 7
To graph:
- put a point on 7, on the y-axis
- From there, you would normally use the slope as rise/run to get another point,
however since the slope is 0, this is a horizontal line.
So, just make a horizontal line through 7 on the y-axis
www.algebrahouse.com
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