Question 433185: The intensity of a TV signal varies inversely as the square of the distance from the transmitter. If the intensity is 23 watts per square meter (w/m^2) at adistance of 2km, what is the intensity at a didtance of 15km
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! The intensity of a TV signal varies inversely as the square of the distance from the transmitter. If the intensity is 23 watts per square meter (w/m^2) at adistance of 2km, what is the intensity at a didtance of 15km
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If this were just a direct proportion, the multiplier for the new intensity would simply be the ratio of the two distances. But in this case, the multiplier is the square of the distance. Also, since this is an inverse relationship, the multiplier is always less than 1.Thus, the new intensity at 15km=(2/15)^2*23=.409..(w/m^2)
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