Question 432993: A pizza parlor runs a special where you buy a large pizza with 1 cheese, 1 vegetable, and 2 meats for $!2. You have a choice of 5 cheeses, 10 vegetables, and 6 meats. How many different variation of pizzas specials are possible?
For this one, I'm not sure, but I tried to multiple 5*10*6=300. However, I need help confirming if i did this problem right. Thanks.
Answer by sudhanshu_kmr(1152) (Show Source):
You can put this solution on YOUR website!
here 2 meats ..
so, no. of different variation = 5C1 * 10C1 * 6C2
( selection of 1 cheese out of 5 , selection of 1 veg from out of 10 and selection of 2 meats out of 6)
= 5 * 10 * 15
= 750
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