SOLUTION: 80/(1+15e^-.06x)=50 ;

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: 80/(1+15e^-.06x)=50 ;       Log On


   

Question 432973: 80/(1+15e^-.06x)=50 ;

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
80%2F%281%2B15e%5E%28-.06x%29%29+=+50
<==> 8%2F5+=+1+%2B+15e%5E%28-.06x%29
<==> 3%2F5+=+15e%5E%28-.06x%29
<==> 1%2F25+=+e%5E%28-.06x%29
<==> -2ln5+=+-0.06x
<==> x+=+%282ln5%29%2F0.06
x = 53.65, to 2 decimal places.