SOLUTION: passes through the point (-1,6) and is perpendicular to the line whose equation is 4x+2y=3.

Algebra ->  Linear-equations -> SOLUTION: passes through the point (-1,6) and is perpendicular to the line whose equation is 4x+2y=3.      Log On


   

Question 432922: passes through the point (-1,6) and is perpendicular to the line whose equation is 4x+2y=3.
Found 2 solutions by Gogonati, robertb:
Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
We know that two lines are perpendicular when the product of their slopes is -1.
First we write 4x+2y=3 in the slope-intercept form:y=-2x%2B3%2F2, we see that
the slope of this line is m1=-2. Let's the slope of the perpendicular line, m2,
then m1*m2=-1, substitute m1=-2, (-2)*m2=-1 => m2=1/2.
Now we find the equation of line through the point (-1, 6) with slope m2=1/2:
y-6=%281%2F2%29%2A%28x%2B1%29, write it in the slope-intercept form.
y=%281%2F2%29%2Ax%2B7, and in the standard form:
x-2y=-14
graph%28300%2C+300%2C+-15%2C+5%2C+-5%2C+10%2C+-2x%2B%283%2F2%29%2C+%281%2F2%29x%2B7%29
Done.

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
the equation of the perpendicular line must be 2x - 4y = c, where c is an unknown constant. To find c, use the coordinates of the given point:
2*-1 -4*6 = c, or -2 - 24 = c, or c = -26.
Hence the equation of the perpendicular line is 2x - 4y = -26, or x - 2y = -13.