SOLUTION: The height of a triangle is 2 meters longer than twice its base. Find the base and height if the area of the triangle is 8 meters.

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Question 432743: The height of a triangle is 2 meters longer than twice its base. Find the base and height if the area of the triangle is 8 meters.
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
CORRECTION. I MISREAD THE VALUE OF [H]. SORRY.
A=BH/2
H=2B+2
8=B(2B+2)/2
8=(2B^2+2B)/2
16=2B^2+2B
2B^2+2B-16=0
2(B^2+B-8)=0
B+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
B=(-1+-SQRT[1^2-4*1*8])/2
B=(-1+-SQRT1+32])/2
B=(-1+-SQRT33)/2
B=(-1+-5.74)/2
B=(-1+5.74)/2
B=4.74/2
B=2.37 ANS. FOR THE BASE.
H=2*2.37+2
H=4.74+2
H=6.74 ANS FOR THE HEIGHT.
PROOF:
8=2.37*6.74/2
8=16/2
8=8