SOLUTION: 1/2[log(x+2)+log(x+3)]=1

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Question 432536: 1/2[log(x+2)+log(x+3)]=1
Found 2 solutions by ewatrrr, nerdybill:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

1/2[log(x+2)+log(x+3)]=1

  log(x+2)*(x+3) = 2

 10^2 = (x+2)*(x+3)

  x^2 + 5x - 94 = 0

 x = 7.5125  |tossing out negative solution as being Extraneous

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
1/2[log(x+2)+log(x+3)]=1
[log(x+2)+log(x+3)]=2
log(x+2)(x+3)=2
(x+2)(x+3)=10^2
x^2+5x+6 = 100
x^2+5x-94 = 0
applying the quadratic formula gives you your answers:
x = {-12.512, 7.512}
then negative solution is extraneous, toss it out leaving:
x = 7.512