SOLUTION: Change from exponential form to logarithmic form and solve for x:
3^x-2=7
A)solve for x (exact solution)
B)use calculator to solve for x and round to nearest thousandth
Am
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: Change from exponential form to logarithmic form and solve for x:
3^x-2=7
A)solve for x (exact solution)
B)use calculator to solve for x and round to nearest thousandth
Am
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Question 432469: Change from exponential form to logarithmic form and solve for x:
3^x-2=7
A)solve for x (exact solution)
B)use calculator to solve for x and round to nearest thousandth
Am I doing this right?
A) log3 of 3^x-2=log3 of 7
x-2=log3 of 7 (+2 to both sides)
x=(log3 of 7)+2
x=(ln7/ln3)+2
Would this be my final answer for A?
B) Same steps as above
x=(ln7/ln3) +2
x=3.771 approximately rounded to the nearest thousandth
I just need to know if I am doing this correctly, and getting the correct solutions. If not I have to figure out where I am going wrong. Please guide me. Answer by MathLover1(20850) (Show Source):
..............is equivalent to...............(means the exact same thing as)
Change from exponential form to logarithmic form and solve for :
A)solve for (exact solution)
B)use calculator to solve for and round to nearest thousandth
................... .............
............