SOLUTION: sin[arccos1/2 + arcsin(-1)]

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Question 432307: sin[arccos1/2 + arcsin(-1)]
Answer by lwsshak3(11628) About Me  (Show Source):
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sin[arccos1/2 + arcsin(-1)]
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Using addition formula for sin: sin(x+y)=sinxcosy+cosxsiny
sin[arccos1/2 + arcsin(-1)]
sin(60+270)=sin60cos270+cos60sin270
=sqrt(3)/2)(0)+1/2(-1)
=0-1/2=-1/2
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