SOLUTION: Please help me solve this problem!!
The sume of the ages of 2 boys is 18. If 4 times the younger boys age is subtracted from 3 times the older boys age, the difference is 12. Wh
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The sume of the ages of 2 boys is 18. If 4 times the younger boys age is subtracted from 3 times the older boys age, the difference is 12. Wh
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Question 432174: Please help me solve this problem!!
The sume of the ages of 2 boys is 18. If 4 times the younger boys age is subtracted from 3 times the older boys age, the difference is 12. What are the ages of the two boys?
Please tell me how to solve this!
I have tried 2x=18 for the first equation
and then 3x-4x=12?
I am so lost
Please get back to me asap
I have class in an hour and a half!!
HELP!! Answer by sudhanshu_kmr(1152) (Show Source):
You can put this solution on YOUR website!
Let age of younger boy =x
age of older boy = y
x+y = 18 ..........(1)
and 3y - 4x = 12 .........(2)
multiply equation 1 by 4 and add both equations
4x + 4y = 72
3y - 4x= 12
then 7y = 84
=> y = 84/7 = 12
x = 18 -12 = 6
age of younger boy is 6, age of older boy is 12.