SOLUTION: Solve each system of equations using Cramer's Rule if it is applicable. If Cramer's Rule is not applicable, say so. x+2y=5 x-y=3

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Question 432065: Solve each system of equations using Cramer's Rule if it is applicable. If Cramer's Rule is not applicable, say so.
x+2y=5
x-y=3

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
Solve system of equations using Cramer's Rule
x+2y=5
x-y=3
x = 11/3 and y = 2/3 See below
Solved by pluggable solver: Using Cramer's Rule to Solve Systems with 2 variables



system%281%2Ax%2B2%2Ay=5%2C1%2Ax%2B-1%2Ay=3%29



First let A=%28matrix%282%2C2%2C1%2C2%2C1%2C-1%29%29. This is the matrix formed by the coefficients of the given system of equations.


Take note that the right hand values of the system are 5 and 3 which are highlighted here:
system%281%2Ax%2B2%2Ay=highlight%285%29%2C1%2Ax%2B-1%2Ay=highlight%283%29%29



These values are important as they will be used to replace the columns of the matrix A.




Now let's calculate the the determinant of the matrix A to get abs%28A%29=%281%29%28-1%29-%282%29%281%29=-3. Remember that the determinant of the 2x2 matrix A=%28matrix%282%2C2%2Ca%2Cb%2Cc%2Cd%29%29 is abs%28A%29=ad-bc. If you need help with calculating the determinant of any two by two matrices, then check out this solver.



Notation note: abs%28A%29 denotes the determinant of the matrix A.



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Now replace the first column of A (that corresponds to the variable 'x') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5Bx%5D (since we're replacing the 'x' column so to speak).


A%5Bx%5D=%28matrix%282%2C2%2Chighlight%285%29%2C2%2Chighlight%283%29%2C-1%29%29



Now compute the determinant of A%5Bx%5D to get abs%28A%5Bx%5D%29=%285%29%28-1%29-%282%29%283%29=-11. Once again, remember that the determinant of the 2x2 matrix A=%28matrix%282%2C2%2Ca%2Cb%2Cc%2Cd%29%29 is abs%28A%29=ad-bc



To find the first solution, simply divide the determinant of A%5Bx%5D by the determinant of A to get: x=%28abs%28A%5Bx%5D%29%29%2F%28abs%28A%29%29=%28-11%29%2F%28-3%29=11%2F3



So the first solution is x=11%2F3




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We'll follow the same basic idea to find the other solution. Let's reset by letting A=%28matrix%282%2C2%2C1%2C2%2C1%2C-1%29%29 again (this is the coefficient matrix).




Now replace the second column of A (that corresponds to the variable 'y') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5By%5D (since we're replacing the 'y' column in a way).


A%5Bx%5D=%28matrix%282%2C2%2C1%2Chighlight%285%29%2C1%2Chighlight%283%29%29%29



Now compute the determinant of A%5By%5D to get abs%28A%5By%5D%29=%281%29%283%29-%285%29%281%29=-2.



To find the second solution, divide the determinant of A%5By%5D by the determinant of A to get: y=%28abs%28A%5By%5D%29%29%2F%28abs%28A%29%29=%28-2%29%2F%28-3%29=2%2F3



So the second solution is y=2%2F3




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Final Answer:




So the solutions are x=11%2F3 and y=2%2F3 giving the ordered pair (11/3, 2/3)




Once again, Cramer's Rule is dependent on determinants. Take a look at this 2x2 Determinant Solver if you need more practice with determinants.