SOLUTION: A bus leaves a station at 1 p.m., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what

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Question 43191This question is from textbook
: A bus leaves a station at 1 p.m., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what time will the two buses by 274 mi apart? This question is from textbook

Found 3 solutions by checkley71, stanbon, Nate:
Answer by checkley71(8403)   (Show Source):
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44(X+1)+48X=274 OR 44X+44+48X=274 OR 92X=230 OR X=230/92 OR X=2.5HOURS FOR BUS GOING EAST THUS THE TIME IS 4:30 WHEN THEY WILL BE 274 MILES APART.

Answer by stanbon(75887)   (Show Source):
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A bus leaves a station at 1 p.m., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what time will the two buses by 274 mi apart?
Bus West DATA:
distance=?; rate=44 mph; time=x----- therefore distance =44x
Bus East DATA:
distance=?; rate=48 mph; time=x-1----- therefore distance = 48(x-1)
EQUATION:
distance west + distance east = 274
44x + 48(x-1)=274
92x=322
x=3.5 hrs
They will be 274 miles apart at 4:30
Cheers,
Stan H.

Answer by Nate(3500)   (Show Source):
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Rate of First bus:
Rate of Second bus:
Equation:

2 hours 30 minutes
3:30 P.M.