Question 431533: x^2+6x-2=(x+p)^2+q find values of p and q please help the answer is p=3 and q=11, but tried to workd out but dont know how thanks
Answer by sudhanshu_kmr(1152)   (Show Source):
You can put this solution on YOUR website!
x^2+6x-2 = (x+p)^2+q
=> x^2+6x-2= x^2 +p^2 + 2px + q
now, compare co-efficient of both sides....
co-efficient of x on LHS = 6, on RHS = 2p
so, 6 = 2p
=> p = 3
similarly constant value on LHS is -2, on RHS is p^2 +q
so, -2 = p^2 +q
=> -2 = 3^2 + q (after putting the value of p)
=> -2 -9 = q
here q = -11
p = 3 and q = -11
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