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Question 431417: Each figure represents a real number and no denominators are 0. Choose the correct statement and briefly explain why the others are not correct.
a) (Ο/Δ)+(Ω/Ο)=(Ο+Ω)/(ΔΟ)
b) (Ο/Δ)+(Ω/Ο)=(Ο+Ω)/(Δ+Ο)
c) (Ο/Δ)+(Ω/Ο)=(ΟΟ+ΩΔ)/(ΔΟ)
Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website!
c is correct.
a & b are not correct.
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b has the wrong denominator.
The den has the wrong structure, it has to be a product of the 2 given DENs.
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a has the wrong numerator.
The DEN in a is correct, but the NUM is not correct. It's not correct because it doesn't match c, which is correct.
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"why it's not correct" is answered without the need for counter examples.
If the problem stated prove it's not correct, or demonstrate that it's not correct, then a counter example would accomplish that.
But, why it's not correct can be answered with "because it's wrong."
Answer by Edwin McCravy(20064)  (Show Source):
You can put this solution on YOUR website! Each figure represents a real number and no denominators are 0. Choose the correct statement and briefly explain why the others are not correct.
a) (Ο/Δ)+(Ω/Ο)=(Ο+Ω)/(ΔΟ)
b) (Ο/Δ)+(Ω/Ο)=(Ο+Ω)/(Δ+Ο)
c) (Ο/Δ)+(Ω/Ο)=(ΟΟ+ΩΔ)/(ΔΟ)
The correct answers should be counterexamples, not just "it has the
wrong denominator":
a) (Ο/Δ)+(Ω/Ο)=(Ο+Ω)/(ΔΟ)
is not correct because
(4/1)+(8/4)=(4+8)/(1*4)
4 + 2 = 12/4
6 = 3
which is false, and so we have a counterexample.
b) (Ο/Δ)+(Ω/Ο)=(Ο+Ω)/(Δ+Ο)
is not correct because
(6/3)+(12/6)=(6+12)/(3+6)
2 + 2 = 18/9
4 = 2
which is false, and so we have a counterexample
c) is correct
Edwin
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