SOLUTION: okay I'm confused, as usual... m^8 --- 9 ------- m^13 --- 18 This should read m^8 over 9 divided by m^13 over 18 Thank you so much....

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Question 43119This question is from textbook Beginning Algebra
: okay I'm confused, as usual...
m^8
---
9
-------
m^13
---
18
This should read m^8 over 9 divided by m^13 over 18
Thank you so much.... This question is from textbook Beginning Algebra

Found 3 solutions by fractalier, stanbon, tutorcecilia:
Answer by fractalier(6550)   (Show Source):
You can put this solution on YOUR website!
We need to invert the denominator and then multiply, so we get
m^8
---
9
-------
m^13
---
18
becoming
(m^8 / 9) * ( 18 / m^13) =
2 / m^5
when the 9 and m^8 cancel...

Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website!
m^8
---
9
-------
m^13
---
18
Invert the denominator and multiply as follows:
[m^8/9]

Answer by tutorcecilia(2152)   (Show Source):
You can put this solution on YOUR website!
Change the division problem into a multiplication by flipping the second fraction:
.
=(m^8/9)(18/m^13)
.
Cancel out the exponents by subtraction:
(m^8-8/9)(18/m^13-8)
=(1/9)(18/m^5)
.
Continue to cancel out:
(1/1)(2/m^5)
.
Multiply straight across:
2/m^5