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| Question 43113:  The approach pattern to an airport requires pilots to set an 11o angle of descent toward a runway. If a plane is flying at an altitude of 9,500 m, at what distance (measured along the ground) from the airport must the pilot decend
 Found 2 solutions by  fractalier, AnlytcPhil:
 Answer by fractalier(6550)
      (Show Source): 
You can put this solution on YOUR website! If you make a diagram, and construct a triangle, the 11° angle of descent equals the 11° in the triangle...we would use the tangent relationship... Let the distance we want to be x.
 Then tan 11° = 9500/x and
 x = 9500/tan 11°
 x = 48873 m or about 49000 meters (about 30 miles!)
Answer by AnlytcPhil(1808)
      (Show Source): 
You can put this solution on YOUR website! 
The approach pattern to an airport requires pilots
to set an 11o angle of descent toward a runway. If
a plane is flying at an altitude of 9,500 m, at what
distance (measured along the ground) from the airport
must the pilot decend 
                                 P
                                  ·
                      ·           | 9500 m 
A        ·     11°                |
·---------------------------------
              x                   B
The plane is at P, the Airport is at A,
B is a point on the ground directly under the plane.
We want to find AB, the length of which we call x
9500 is the opposite side to 11°
x is the adjacent side to 11°
  tan(11°) = opposite/adjacent
  tan(11°) = 9500/x
x·tan(11°) = 9500 
         x = 9500/tan(11°)
         x = 48873.26315 m or about 48900 meters.
Edwin
AnlytcPhil@aol.com
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