Question 43113: The approach pattern to an airport requires pilots to set an 11o angle of descent toward a runway. If a plane is flying at an altitude of 9,500 m, at what distance (measured along the ground) from the airport must the pilot decend
Found 2 solutions by fractalier, AnlytcPhil: Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! If you make a diagram, and construct a triangle, the 11° angle of descent equals the 11° in the triangle...we would use the tangent relationship...
Let the distance we want to be x.
Then tan 11° = 9500/x and
x = 9500/tan 11°
x = 48873 m or about 49000 meters (about 30 miles!)
Answer by AnlytcPhil(1806) (Show Source):
You can put this solution on YOUR website!
The approach pattern to an airport requires pilots
to set an 11o angle of descent toward a runway. If
a plane is flying at an altitude of 9,500 m, at what
distance (measured along the ground) from the airport
must the pilot decend
P
·
· | 9500 m
A · 11° |
·---------------------------------
x B
The plane is at P, the Airport is at A,
B is a point on the ground directly under the plane.
We want to find AB, the length of which we call x
9500 is the opposite side to 11°
x is the adjacent side to 11°
tan(11°) = opposite/adjacent
tan(11°) = 9500/x
x·tan(11°) = 9500
x = 9500/tan(11°)
x = 48873.26315 m or about 48900 meters.
Edwin
AnlytcPhil@aol.com
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