SOLUTION: which 3 consecutive numbers have a sum of 720

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Question 430961: which 3 consecutive numbers have a sum of 720
Found 2 solutions by josmiceli, algebrahouse.com:
Answer by josmiceli(19441) About Me  (Show Source):
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Let the numbers be n, n%2B1, and n%2B2
+n+%2B+n+%2B+1+%2B+n+%2B+2+=+720+
+3n+%2B+3+=+720+
+3n+=+717+
+n+=+239+
+n+%2B+1+=+240+
+n+%2B+2+=+241+
The numbers are 239,240, and 241

Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
"which 3 consecutive numbers have a sum of 720"

x = 1st consecutive integer
x + 1 = 2nd consecutive integer
x + 2 = 3rd consecutive integer

x + x + 1 + x + 2 = 720 {sum of the three consecutive integers is 720}
3x + 3 = 720 {combined like terms}
3x = 717 {subtracted 3 from both sides}
x = 239 {divided both sides by 3}
x + 1 = 240 {substituted 239, in for x, into x + 1}
x + 2 = 241 {substituted 239, in for x, into x + 2}

239, 240, and 241 are the three integers
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