SOLUTION: 10 over t^7 times 3t^2 over 25t = show work
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Question 43064
:
10 over t^7 times 3t^2 over 25t =
show work
Answer by
fractalier(6550)
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You can
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We can multiply and then cancel...or we can cancel first...
10 / t^7 * 3t^2 / 25t =
30t^2 / 25t^8 =
now 30/25 reduces to 6/5 and t^2 cancels, so we have
6 / 5t^6