You can put this solution on YOUR website! Determine the nature of the solutions of the equation.
y^2=(1/8)y+3/5
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Multiply thru by 40 to get:
40y^2 = 5y + 24
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40y^2-5y+24 = 0
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Check the determinant:
b^2-4ac = 25-4*50*24 < 0
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So It has two unequal complex roots.
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Cheers,
Stan H.