SOLUTION: Give exact and appropriate solutions to three decimal places. y^2-4y+4=1 Thank you

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Question 430481: Give exact and appropriate solutions to three decimal places.
y^2-4y+4=1
Thank you
Answer by sudhanshu_kmr(1152) About Me  (Show Source):
You can put this solution on YOUR website!

y^2-4y+4=1
=> y^2-4y+3=0
=> y^2 -3y -y +3 = 0
=> y(y-3) -1(y-3) =0
=> (y-3)(y-1)= 0
so, y = 3 or y = 1