SOLUTION: Find two consecutive positive and odd integers such that the difference of their squares is 64

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Question 430459: Find two consecutive positive and odd integers such that the difference of their squares is 64
Found 2 solutions by Alan3354, Gersid:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
64/4 = 16, the center
--> 15 & 17

Answer by Gersid(33) About Me  (Show Source):
You can put this solution on YOUR website!
Let the smaller odd integer be x, then the next consecutive odd integer is x+2.
x%2B2%29%5E2-x%5E2+=+64 "...the difference of their squares is 64"
%28x%5E2%2B4x%2B4%29-x%5E2+=+64
4x%2B4+=+64
4x+=+60
x+=+15 and x%2B2+=+17