SOLUTION: {{{(x^2-3x-28)/(16-x^2)}}} =y For this problem, what would the removable discontinuity be? Thank you and have a great day!

Algebra ->  Rational-functions -> SOLUTION: {{{(x^2-3x-28)/(16-x^2)}}} =y For this problem, what would the removable discontinuity be? Thank you and have a great day!      Log On


   

Question 430404: %28x%5E2-3x-28%29%2F%2816-x%5E2%29 =y
For this problem, what would the removable discontinuity be? Thank you and have a great day!
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
. There is a hole on the graph of y = f(x) at x = -4, and hence that is where the removable discontinuity is. (There is an essential discontinuity at x = 4, or a vertical asymptote there.)