SOLUTION: Multiply ((x^(2)z^(2)~(x)+y^(7)))/(x^(5)z^(2)) by (x^(9)z^(9))/(y^(2)) to get (x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2)).
((x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2)))
Remove the
Algebra ->
Exponents-negative-and-fractional
-> SOLUTION: Multiply ((x^(2)z^(2)~(x)+y^(7)))/(x^(5)z^(2)) by (x^(9)z^(9))/(y^(2)) to get (x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2)).
((x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2)))
Remove the
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Question 430343: Multiply ((x^(2)z^(2)~(x)+y^(7)))/(x^(5)z^(2)) by (x^(9)z^(9))/(y^(2)) to get (x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2)).
((x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2)))
Remove the parentheses around the expression (x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2)).
(x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2))
- I don't how this part works: Multiply ((x^(2)z^(2)~(x)+y^(7)))/(x^(5)z^(2)) by (x^(9)z^(9))/(y^(2)) to get (x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2)).
How do you get x^4z^7? Wouldn't you get x^11z^11????? HELP! Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website! I recommend you repost your question. First of all, you have far too many parentheses, and it looks jumbled up and I don't even want to try to decipher what you are writing. Also, what does the symbol ~ stand for?
You can always try wrapping your equations around three curly braces to produce neater expressions.
