SOLUTION: 3(x+1)^2+3(y-1)^2=6

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Question 43033This question is from textbook Algebra & Trigonometry
: 3(x+1)^2+3(y-1)^2=6 This question is from textbook Algebra & Trigonometry

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
From the equation
3(x+1)^2 + 3(y-1)^2 = 6
we divide everything by 3 and get
(x+1)^2 + (y-1)^2 = 2
This is the equation of a circle
with center at (-1, 1) and
radius of sqrt(2).