SOLUTION: Please help me solve this equation: The three sides of a right triangle are represented by x, x+4, and x+8. Find the value of X and the three sides of the triangle algebraically

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Question 430207: Please help me solve this equation:
The three sides of a right triangle are represented by x, x+4, and x+8. Find the value of X and the three sides of the triangle algebraically.
So far this is what I have:
a^2+b^2=c^2
X^2+(x+4)(x+4)= (x+8)(x+8)

Found 2 solutions by ewatrrr, Sphinx pinastri:
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!

Hi
a^2+b^2=c^2
x^2+(x+4)(x+4)= (x+8)(x+8) |good work on the Set Up
x^2 + x^2 + 8x+ 16 = x^2 + 16x + 64
x^2-8x-48 = 0
factoring
(x+4)(x-12) = 0
(x+4)= 0 x = -4 |tossing out negative solution for length
(x-12) = 0 x = 12
three sides are 12, 16 and 20
CHECKING our Answer***
12^2 + 16^2 = 144 + 256 = 20^2 = 400

Answer by Sphinx pinastri(17) (Show Source):
You can put this solution on YOUR website!
That's right. You just need to solve the square equation.

Another root is negative.