SOLUTION: Part of $15,000 is invested at 8% annual interest, and the rest is invested at 6%. After one year, the accounts paid $1,000 in interest. How much was invested at the lower rate?

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Part of $15,000 is invested at 8% annual interest, and the rest is invested at 6%. After one year, the accounts paid $1,000 in interest. How much was invested at the lower rate?      Log On

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Question 430149: Part of $15,000 is invested at 8% annual interest, and the rest is invested at 6%. After one year, the accounts paid $1,000 in interest. How much was invested at the lower rate?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Part I 8.00% per annum
Part II 6.00% per annum

x+y=15000------------------------1
8.00%x+ 6.00%y=$1,000.00
Multiply by 100
8x+6y=$100,000.00--------2

Multiply (1) by -8
we get

-8x-8y=-120000.00

Add this to (2)

-2y=-$20,000.00

divide by -2

y=$10,000.00 investment at 6.00%
Balance $5,000.00 investment at 8.00%