SOLUTION: how many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 80% antifreeze?
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Question 430092: how many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 80% antifreeze? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! how many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 80% antifreeze?
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Equation:
alcohol + alcohol = alcohol
0.90x + 0.10*60 = 0.80*(x+60)
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Multiply thru by 100:
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90x + 10*60 = 80x+80*60
10x = 70*60
x = 420 gallons (amt. of 90% solution needed)
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Cheers,
Stan H.
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