Question 430057: Jose has 22 coins totaling $4.10. If all of the 22 coins are either nickles or quarters, how many of each coin does he have? You must define the variable first and then solve for variable.
Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! If Jose has 22 coins, then
X+Y=22
If all the coins are either nickles or quarters, then
.25X+.05Y=4.10
Multiply the second equation by 100, we get
25X+5Y=410
Take the first equation and multiply by 5 we get
5X+5Y=110
Subtract the first equation from the second, we get
20X=300
X=15
So we have 15 quarters (X) and 22-15, or 7 nickels (Y).
|
|
|