SOLUTION: Find the vertex and focus of the parabola x2 - 16y=0

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Question 429647: Find the vertex and focus of the parabola x2 - 16y=0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi



 The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29, where  the focus is (h,k + p) 

 x^2 = 16y   | Vertex is Pt(0,0), p = 4 and focus is Pt(4,0)