SOLUTION: solve each system of equations by substitution help i cant figure this out i have the formulas but dont seem to work out right
5x+10y=20
2x+6y=10
6y=-2x+10
y=-1/3x +5/3
5x
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-> SOLUTION: solve each system of equations by substitution help i cant figure this out i have the formulas but dont seem to work out right
5x+10y=20
2x+6y=10
6y=-2x+10
y=-1/3x +5/3
5x
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Question 429477: solve each system of equations by substitution help i cant figure this out i have the formulas but dont seem to work out right
5x+10y=20
2x+6y=10
6y=-2x+10
y=-1/3x +5/3
5x+10(1/3x+5/3)=20
5x+ Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! 5 x + 10 y = 20 .............1
2 x + 6 y = 10 .............2
Eliminate y
multiply (1)by -3
Multiply (2) by 5
-15 x + -30 y = -60
10 x + 30 y = 50
Add the two equations
-5x=-10
/-5
x=2
plug value of x in (1)
5x+10y=20
10+10y= 20
10y=20-10
10y=10
y=1
CHECK
5x+10y= 20
10+10 =20
20 = 20
The rest of them are to be solved in the same way
