SOLUTION: A Ricoh copier can complete a job in 10 minutes. A xerox machine can do the same job in 12 minutes. A worker needs a job completed in 5 minutes. If both copiers work on the job at

Algebra ->  Rational-functions -> SOLUTION: A Ricoh copier can complete a job in 10 minutes. A xerox machine can do the same job in 12 minutes. A worker needs a job completed in 5 minutes. If both copiers work on the job at       Log On


   



Question 429347: A Ricoh copier can complete a job in 10 minutes. A xerox machine can do the same job in 12 minutes. A worker needs a job completed in 5 minutes. If both copiers work on the job at the same time, will the worker have the job done in time? Explain with work shown.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A Ricoh copier can complete a job in 10 minutes.
A xerox machine can do the same job in 12 minutes.
A worker needs a job completed in 5 minutes.
If both copiers work on the job at the same time, will the worker have the job done in time?
Explain with work shown.
:
Let t = time required with both copiers operating
Let the completed job = 1
:
Each copier will do a fraction of the job, the two factions must add up to 1
t%2F10 + t%2F12 = 1
To clear the denominators, multiply by 60, results:
6t + 5t = 60
11t = 60
t = 60%2F11
t = 5.45 min, so not quite