SOLUTION: Find the point on the circle with the equation x^2 +Y^2= 1 that is closest to the point (4,3)

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Question 429337: Find the point on the circle with the equation x^2 +Y^2= 1 that is closest to the point (4,3)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the point on the circle with the equation x^2 +Y^2= 1 that is closest to the point (4,3)
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The point on the circle will be on a line thru (4,3) and the center of the circle.
The center is (0,0)
The distance from (0,0) is 5 = sqrt%284%5E3+%2B+3%5E2%29
The point on the circle is 1 unit from the center with the x/y ratio of 4/3
--> (4/5,3/5) or (0.8,0.6)